ldls: the stubs, and the driver's own voice

docs/plan/ldls.md milestone L1. Every undefined symbol resolves to a
trampoline -- twenty generated bytes that load the symbol's index and jump to
a shared thunk, which saves the argument registers and reports the call. Then
init_module is simply called.

    $ ldls-run 8139too.ko
      module  8139too
      license GPL
      wants   94 symbols
      calling init_module at 0x416fc020

        1  _printk(0x416fb6c0, 0, 0)
          | 8139too: 8139too Fast Ethernet driver 0.9.28
        2  __pci_register_driver(0x416fb400, 0x416fff80, 0x416fbdbb)

      init_module returned 0 after 2 stub call(s)

That second line is the driver's own banner, printed through a _printk that
is ours, from a string in the module's own .rodata that a relocation put
there. There is no stronger evidence that a load worked than the loaded thing
speaking.

Stubs return zero rather than stopping, which departs from what the milestone
originally said and does so deliberately: stopping at the first call tells you
one name, carrying on tells you the sequence, and the sequence is the thing a
symbol table cannot give you. A driver that then dereferences the zero faults,
and that is a result too -- it says how far it got before it needed the kernel
to have really done something.

The first run failed on neither of those. It failed on a relocation:

    ldls-run: relocate: a signed 32-bit relocation does not fit

A module is compiled -mcmodel=kernel, so the compiler emits R_X86_64_32S for
anything it believes lives in the top 2 GB, and an ordinary mmap at 0x7f...
has nowhere to put it. Linux gives modules a region within 2 GB of the kernel
text; the harness uses MAP_32BIT to reach the same window from the other end.
On SchOS this costs nothing -- a process's mmap area starts at 0x40000000 and
is already inside it -- but it is a real constraint on where the host may load
a module, and a loader that did not check its own arithmetic would have found
it much later and much more confusingly.

Swept over 500 stock modules: 449 ran init to completion, 22 faulted on a
stub's zero, 29 have no init_module, and zero hit a loader error.

Recorded honestly in "what it will not do": running init is not working. Every
symbol is a stub, so what has been shown is that drivers ask for things in a
readable order, not that anything answers. Also recorded: every undefined
symbol in a module is NOTYPE, so the stubs cannot tell jiffies from
pci_iomap and both get a trampoline -- BTF distinguishes VAR from FUNC and
that is where the fix belongs rather than in a guess.

make ldls-check is 23 checks now, five of them L1's, all against
ldls/test/refmod.c which is ours and now has an init_module of its own.

Co-Authored-By: Claude Opus 5 <noreply@anthropic.com>
Claude-Session: https://claude.ai/code/session_01VQ7Qx8E1q1M1bbCq8QLHS2
This commit is contained in:
Nexoniarz 2026-09-14 08:02:29 +02:00
commit 7a7c7611e0
8 changed files with 636 additions and 10 deletions

View file

@ -99,6 +99,33 @@ def main():
r3 = subprocess.run([inspect, sys.argv[0]], capture_output=True, text=True)
need(r3.returncode != 0, "a non-ELF file is refused, not parsed")
# --- L1: the object is loaded and its init actually runs ----------------
if len(sys.argv) < 4:
print("ldls-check: %d checks passed (L0 only -- no ldls-run given)"
% checks)
return 0
run = sys.argv[3]
r4 = subprocess.run([run, obj], capture_output=True, text=True)
out = r4.stdout
need(r4.returncode == 0, "ldls-run loads the object and returns cleanly")
need("calling init_module" in out, "it finds and calls init_module")
need("init_module returned 0" in out,
"init runs to the end and returns what it meant to")
# The call *order*, which is the whole point of L1: a symbol list is a set
# and says nothing about sequence.
seq = re.findall(r"^\s+\d+\s+(\w+)\(", out, re.M)
need(seq == ["ldls_test_print", "ldls_test_alloc", "ldls_test_free"],
"the stub calls are reported in the order the code makes them")
# Arguments survive the trampoline and the thunk. If the register save were
# wrong this is where it would show, because the first argument is a real
# pointer into the loaded object rather than a small integer.
m = re.search(r"ldls_test_print\((0x[0-9a-f]+)", out)
need(m is not None and int(m.group(1), 16) != 0,
"arguments reach the stub intact, not zeroed by the thunk")
print("ldls-check: %d checks passed" % checks)
return 0