SchOS/kernel/net/lwip/shim/stdlib.h
Nexoniarz 26bca020b6 licence: SchOS is GPL-2.0-or-later, no longer Apache-2.0
Nexoniarz is the sole author and SchOS was never published under
Apache-2.0, so this is a straight relicence. LICENSE is the FSF GPLv2 text,
every first-party SPDX header moves to GPL-2.0-or-later, and NOTICE,
README.md, docs/licensing.md and the site say so. projects/schfs-linux
follows the rest of the tree.

The GPL gives copyleft: a fork has to ship its source. It also lifts the
old "Linux drivers, never" rule, since GPL-2.0-only code combines with
GPL-2.0-or-later. "Or later" leaves room for GPLv3, but one binary still
has to pick one version, so docs/licensing.md now keeps Apache-2.0 and
GPLv3 code out of the kernel to keep Linux code possible there. BSD
4-clause code goes from "avoid" to "no", because the advertising clause
is GPL-incompatible.

LDLS still ships no .ko. That boundary is now project policy rather than
a legal requirement, and ldls.md, devices.md and licensing.md section 6
say so. refmod declares license=GPL, and ldls-check passes (27 checks).

Co-Authored-By: Claude Opus 5.5 <noreply@anthropic.com>
2026-10-22 08:48:45 +02:00

28 lines
996 B
C

// SPDX-License-Identifier: GPL-2.0-or-later
//
// <stdlib.h> for lwIP, shadowing the host's. See shim/string.h for why these
// files exist at all.
//
// lwIP does not need an allocator from here: MEM_LIBC_MALLOC is off, so it uses
// its own pools out of a static heap. That is not a workaround -- the kernel's
// allocator hands out whole pages and lwIP wants byte granularity, so its pools
// are the better fit either way.
//
// atoi is the one thing it genuinely calls, in netif_name_to_index, to turn the
// digits at the end of an interface name into a number.
#ifndef LWIP_SHIM_STDLIB_H
#define LWIP_SHIM_STDLIB_H
// Deliberately not a general atoi: no sign, no whitespace, no overflow
// handling. It is fed the tail of an interface name ("en0" -> "0"), and
// anything cleverer would be untested code answering a question nobody asks.
static inline int
atoi(const char *s)
{
int n = 0;
while (*s >= '0' && *s <= '9')
n = n * 10 + (*s++ - '0');
return n;
}
#endif